UNIX for Dummies Questions & Answers

Hi all,

i executed a script.

cat <filename> | grep <pattern> | awk '{print $1}' | read a

i get the answer when i execute it in the shell env (no problem with that)
as
./<name>.ksh

when i tried the same in cron (as an entry in cron)
value is not being read in the variable a through read statement.

the variable a remains an empty variable.

Can u please help me with this.
Thanks.

First line of the script must be:
#! /usr/bin/ksh
and the script must be executable, ie, have execute permission turned on.