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Script to count character present in a line

 
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# 1  
Old 11-08-2012
Script to count character present in a line
Suppose i have multiple line like below in a file.
ASDFAFAGAHAHAHA
AGAHAHAJGAFAGAH
AHAHAKAHAHAHAKA
I need a bash script to count a character and also Also count the number of character present in each line .
suppose for line 1: A=x, S=y, D=x and so on and total character=15. where x y and z is the occurance in line 1. I need to do for all line in same fashion.

I will be thankful if anyone can help me.

regards,
XXlMMN
# 2  
Old 11-08-2012
Is this what you want..?

Code:
awk -F "" '{for(i=1;i<=NF;i++){X[$i]++}for(i in X){s=s?s" "i" "X[i]:i" "X[i];delete X[i]}print NF,s;s=""}' file


Code:
awk '{for(i=1;i<=length($0);i++){X[substr($0,i,1)]++}for(i in X){s=s?s" "i" "X[i]:i" "X[i];delete X[i]}print length($0),s;s=""}' file

This User Gave Thanks to pamu For This Post:
XXLMMN
# 3  
Old 11-08-2012
Quote:
Originally Posted by pamu
Is this what you want..?

Code:
awk -F "" '{for(i=1;i<=NF;i++){X[$i]++}for(i in X){s=s?s" "i" "X[i]:i" "X[i];delete X[i]}print NF,s;s=""}' file


Code:
awk '{for(i=1;i<=length($0);i++){X[substr($0,i,1)]++}for(i in X){s=s?s" "i" "X[i]:i" "X[i];delete X[i]}print length($0),s;s=""}' file

Thank you for help but can i print like A=x instead A x
# 4  
Old 11-08-2012
Quote:
Originally Posted by XXLMMN
Thank you for help but can i print like A=x instead A x
Yes..Smilie

Just replace space with =

Code:
awk -F "" '{for(i=1;i<=NF;i++){X[$i]++}for(i in X){s=s?s" "i"="X[i]:i"="X[i];delete X[i]}print NF,s;s=""}' file

Code:
awk '{for(i=1;i<=length($0);i++){X[substr($0,i,1)]++}for(i in X){s=s?s" "i"="X[i]:i"="X[i];delete X[i]}print length($0),s;s=""}' file

This User Gave Thanks to pamu For This Post:
XXLMMN
 
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