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List only files based on a pattern

 
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# 1  
Old 10-09-2012
List only files based on a pattern
Hi Gurus,

I need to list only the files with out certain extension.

For eg from the following list of files:

Quote:
file1
file1.20120130
file1.20120225
file2
file2.20120115
file2.20120320
I need to only list:

Quote:
file1
file2
Thanks
Shash
# 2  
Old 10-09-2012
Use the "find" command.

You can find a short introduction to "find" here.

I hope this helps.

bakunin
# 3  
Old 10-09-2012
Apologies, if I 'm not clear enough. I have thousands of file with different names. I need to find the files with out a decimal place followed by a date in the file name which has been showed in the example.
# 4  
Old 10-09-2012
if the extension of the .txt file...
try like...
Code:
 ls test?.???

---------- Post updated at 07:40 AM ---------- Previous update was at 07:36 AM ----------

if is numbers only try like..

Code:
ls test[1-9].???

# 5  
Old 10-09-2012
Code:
ls | awk -F. 'NF==1'

# 6  
Old 10-09-2012
If you can use ls, try:
Code:
ls !(*.*)

Note: Turn on extglob in bash (shopt -s extglob).
# 7  
Old 10-09-2012
Thanks all it worked Smilie
 
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