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NEWB Question - BASH COMMAND RESULT for ${0##*/}

 
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# 1  
Old 09-25-2012
Question NEWB Question - BASH COMMAND RESULT for ${0##*/}
This should be extremely simple and someone will probably answer it in .5 seconds. I need to know what:

Code:
VARIABLE=${0##*/}

does? I do not have a shell handy to just try it in. I am reading through some scripts and need to understand this line. Any help is appreciated.

Many thanks!

- Chris
# 2  
Old 09-25-2012
See the Advanced BASH Scripting Guide -- String Operations.
This User Gave Thanks to Corona688 For This Post:
chrisgoetz
# 3  
Old 09-25-2012
Quote:
Originally Posted by Corona688
See the Advanced BASH Scripting Guide -- String Operations.
Thanks, Corona. Didn't even realize that squiggly braces were for string substitution, it's been a while since I've done shell scripting, just getting back into it. So my understanding is that this should get the current executing script and strip everything off the beginning, leaving just the filename, correct?
Last edited by chrisgoetz; 09-25-2012 at 05:34 PM..
# 4  
Old 09-25-2012
Not necessarily for string substitution. $VAR and ${VAR} amount to the same thing for example. But you can put things inside ${VAR} which do string substitution.

And I think you're right on the money.
 
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