Du -sk command in SunOS 5.10

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# 1  
Du -sk command in SunOS 5.10


I am little confuse after using
du -sk on file .

I have file listing like:
-rw-r--r-- 1 Xuser Ygrp 51419029531 Sep 21 07:40 catalina.out

when i issue cmd :
du -sk catalina.out

gives output as
1804511 catalina.out

This means 1804511 KB. Which means 1 GB.

But if i calculate using 51419029531 bytes / 1024 bytes = 50213896.0 KB

50213896.0/1024=49037 MB

49037/1024= 47 GB

It shows 47 GB but du shows 1 GB.

Please let me know where I am doing wrong.


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Last edited by vbe; 09-21-2012 at 04:47 AM..
# 2  
try this also...

stat -c%s catalina.out

ls -lh catalina.out

du -h catalina.out

# 3  
You will have to explain how you got your first figure...

slo4:/export/home/vbe $ uname -r
slo4:/export/home/vbe $ ls -l amanda-3.3.0.tar.gz
-rwxr-xr-x   1 vbe      sysadm   4193702 Nov  7  2011 amanda-3.3.0.tar.gz
slo4:/export/home/vbe $ du -sk amanda-3.3.0.tar.gz
4100    amanda-3.3.0.tar.gz

# 4  
Might be a "sparse file", i.e. a file with holes in it. List it with ls -s, col 1 will show the actually used blocks on disk, as does du, col 5 will show what the file system thinks the size is:
$ ls -ls fn
8 -rw-r--r-- 1 root root 4194339 Sep 21 09:56 fn
$  du -sk fn
8    fn


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