UNIX for Dummies Questions & Answers

Hello,

Here is my question. I have a file which contains the html values. I have to find the decimal number from it. It is tagged around >68.74<. Please help me on it..

Code:

alt=''  ><\/td>\n\t\t<td  align=\"right\" class='data_table_text data_table_conv_averages_text' \
style='padding-right: 2px;'>68.74<\/td>\n\t<\/tr>\n\t<tr>\n\t\t<td colspan='4'>\n\t\t\t<table cellspacing=0\
 cellpadding=0 border=0 width='100%'>\n\t\t\t\t<tr><td

I have tried

Code:

grep -o '[0-9][0-9]\.[0-9][0-9]' filename

it doesn't help with what i am looking for.. Since it brings all the values

In this case I am aware it is of [0-9][0-9].[0-9][0-9]..

How can i use my command so that it finds all the decimal numbers which are tagged around > < [no matter how many digits will be]

---------- Post updated at 03:41 AM ---------- Previous update was at 03:30 AM ----------

Ah i found out...

Code:

grep -o '>[0-9]*\.[0-9]*<'

Please correct me if this works..

>[0-9]*\.[0-9]*< is not a totally fire-proof regexp though it will work for your input. This will also match >.< although this might never occur in your input file. A better regexp would be >[0-9][0-9]*\.[0-9][0-9]*<.