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is there a way to assing variable a value that is output of a program in awk script?

 
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# 1  
Old 08-04-2012
is there a way to assing variable a value that is output of a program in awk script?
Hi there is there a way to assing variable a value that is output of a program in awk script. For e.g., I did
Code:
 temp=(`grep "[datafeed.php]" $5 | cut -f8 -d' '`)

but it does not work.
Any advice???
Thanks in advance!!! Smilie
# 2  
Old 08-04-2012
Either
Code:
temp=`grep "[datafeed.php]" $5 | cut -f8 -d' '`
or 
 temp=$(grep "[datafeed.php]" $5 | cut -f8 -d' ')

would assign the value of the 8th field in the matching line, provided there was one.
This User Gave Thanks to Skrynesaver For This Post:
FUTURE_EINSTEIN
# 3  
Old 08-04-2012
Quote:
Originally Posted by Skrynesaver
Either
Code:
temp=`grep "[datafeed.php]" $5 | cut -f8 -d' '`
or 
 temp=$(grep "[datafeed.php]" $5 | cut -f8 -d' ')

would assign the value of the 8th field in the matching line, provided there was one.
Thanks a lot !!! Smilie
# 4  
Old 08-05-2012
Try using the awk -v temp=$temp option, if it works on your system.
grep may output several lines if there are several matches in $5 so temp might end up with several blank separated data which in turn would inhibit above option.
From the linux mawk man page:
Quote:
command | getline var : pipes a record from command into var.
might give you the desired result.
Last edited by RudiC; 08-05-2012 at 07:41 AM..
 
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