How to get value from set of values in csh


 
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# 1  
Old 08-04-2012
How to get value from set of values in csh

Hello.
In csh if I declared a variable to be a set of arguments can I retrieve a particular element from that set.
My code
Code:
set files=(`ls`)

and I want to get only one file from $files. How can I do that????(It is just an abstract example)Smilie
Thanks in advance Smilie
# 2  
Old 08-04-2012
How do you want to indentify the field to extract, by position, by name, ...
# 3  
Old 08-04-2012
Quote:
Originally Posted by RudiC
How do you want to indentify the field to extract, by position, by name, ...
Thanks for answering but sorry I did not get is it possible or not I wanted to identify it by position
# 4  
Old 08-04-2012
One option - which I don't know if it works in csh - would be to assign the whole stuff to an array and then access array [position]:
Code:
ar=($(echo $files))
echo ${ar[17]}

You have to verify this in csh.
This User Gave Thanks to RudiC For This Post:
# 5  
Old 08-04-2012
Code:
#This is an array in csh
set files = (`ls`)

#The number of elements in the array files
echo $#files

#element 4 in the array files
echo $files[4]

#elements 1 though 3 of the array files
echo $files[1-3]

This User Gave Thanks to xbin For This Post:
# 6  
Old 08-04-2012
Quote:
Originally Posted by RudiC
One option - which I don't know if it works in csh - would be to assign the whole stuff to an array and then access array [position]:
Code:
ar=($(echo $files))
echo ${ar[17]}

You have to verify this in csh.
Thanks a lot!Smilie

---------- Post updated at 09:52 AM ---------- Previous update was at 09:51 AM ----------

Quote:
Originally Posted by xbin
Code:
#This is an array in csh
set files = (`ls`)

#The number of elements in the array files
echo $#files

#element 4 in the array files
echo $files[4]

#elements 1 though 3 of the array files
echo $files[1-3]

Thanks a lot!!! Smilie
 
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