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date format

 
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# 1  
Old 07-26-2012
date format
i want to format the date is like as 'YYYYMMDD'

the date is coming from another variable

how to format the date
# 2  
Old 07-26-2012
A couple of questions that might elicit a more useful response:
  1. What format is the date in the other variable ?
  2. What language/shell are you using?
# 3  
Old 07-26-2012
1. the other format is DD-MON-YYYY
2. yes, i am using korn shell script
# 4  
Old 07-26-2012
Well, not sure of array handling in ksh, but the following works under ksh:
Code:
$  echo $var
26-Jul-2012
$ perl -e '%months=qw(Jan 01 Feb 02 Mar 03 Apr 04 May 05 Jun 06 Jul 07 Aug 08 Sep 09 Oct 10 Nov 11 Dec 12); 
> ($day,$mon,$year)=($ARGV[0]=~/(\d+)-(\w+)-(\d+)/) ;
>print $year,$months{$mon},$day,"\n";' $var  
20120726

# 5  
Old 07-29-2012
more easier way using bash.

Code:
$ cat formdate

#!/usr/bin/bash
var=26-JUL-2012
newvar=$(date --d=$var +'%Y%m%d')
echo $newvar

Code:
$ ./formdate
20120726

# 6  
Old 07-29-2012
Quote:
Originally Posted by Irishboy24
more easier way using bash.

Code:
$ cat formdate

#!/usr/bin/bash
var=26-JUL-2012
newvar=$(date --d=$var +'%Y%m%d')
echo $newvar

Code:
$ ./formdate
20120726

That is using a feature of the date utility on your system; not a feature of bash. On systems that don't have the --d option to date, the following ksh
script should work:
Code:
cat formdate

#!/bin/ksh
# input argument format MM-<Abbreviated_Month>-YYYY
# output format YYYYMMDD
typeset -A month
month=( [JAN]=01  [FEB]=02  [MAR]=03  [APR]=04  [MAY]=05  [JUN]=06
	 [JUL]=07  [AUG]=08  [SEP]=09  [OCT]=10  [NOV]=11  [DEC]=12 )
while [ $# -gt 0 ]
do
	abmon=${1%-*}
	abmon=${abmon#*-}
	printf "%s%s%s\n" "${1##*-}" "${month[$abmon]}" "${1%%-*}"
	shift
done

Code:
formdate 26-JUL-2012 01-JAN-2000 31-DEC-2013
20120726
20000101
20131231

# 7  
Old 08-01-2012
Bug
date '+%m %d %c' | awk '{print $7,$1,$2}'| tr -d ' '
20120801
simpler way to do that i hope so
 
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