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Checking if multiple directories exist

 
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# 1  
Old 07-24-2012
Checking if multiple directories exist
I need to create multiple directories if those directories do not exist already. How would you go by doing this.

What I have so far.

Code:
array=(one two three)

for I in ${array[@]}
do 
   if [[ ! -d ${I} ]]
   then
   mkdir ${I}
   fi
done

I have a good feeling this is done incorrectly. The error I am receiving is "syntax error near unexpected token 'fi'"
# 2  
Old 07-24-2012
Try adding quotes around your variable. This worked for me without any errors:

Code:
array=(one two three)

for I in ${array[@]}
do
    if [ ! -d "$I" ]
    then
        mkdir -v "$I"
    fi
done

mkdir: created directory ‘one'
mkdir: created directory ‘two'
mkdir: created directory ‘three'

# 3  
Old 07-24-2012
Do you even need an array? Or a loop? mkdir can be fed more than one thing at a time, can be told to skip dirs that already exist with -p, and the shell automatically splits on spaces without the help of an array. So, you can do this all in one op without arrays.

Code:
DIRS="a b c"

if ! mkdir -v -p $DIRS
then
        echo "Problem creating $DIRS"
        exit 1
fi

 
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