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Exclude new line character while searching

 
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# 1  
Old 06-29-2012
Exclude new line character while searching
Hi,

I have a log file and want to search "0.48976360737438795" with excluding new line character.
Currently i am using the following command:
Code:
cat LogFile.log | tr -d '\n' | grep '0.48976360737438795'

This command giving me the response if file size is small but if i am using a big file like in GB then it is not giving any response.
I have attached the log file.

Can anyone please help me on this?
Last edited by vbe; 06-29-2012 at 10:02 AM.. Reason: code tags
# 2  
Old 06-29-2012
Hi Ankit,

can you show here your expected result?

Regards,
Dave Null
# 3  
Old 06-29-2012
It should return everything whatever in the attached log file because my search string available in the every log step.
# 4  
Old 06-29-2012
Attachment ?? Also provide sample expected output ..
# 5  
Old 06-29-2012
I'm not sure why you would want to display everything in your screen when the size of the file is in GB.

Perhaps you can add "less" in your command, as it does not read the whole file before displaying.
Code:
cat LogFile.log | tr -d '\n' | grep '0.48976360737438795' | less

Last edited by vbe; 06-29-2012 at 10:03 AM..
# 6  
Old 06-29-2012
Once you remove all the text file line terminators the file is no longer a standard unix text file and is unsuitable for processing in unix shell tools.

What is the record format of the input file? Is is fixed length records or variable length records?

A possible method might be to create two versions of the input file, one with every even numbered line terminator removed and one with every odd numbered line terminator removed. Then search both files to determine if the string is present.
# 7  
Old 07-02-2012
I have attached the Input file and expected output file.
Please help me on this.
Input.txt (7.3 KB) 
Expected_Output.txt (6.6 KB) 
 
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