UNIX for Dummies Questions & Answers

Hi all

I am working on disallowing users to use easy passwords in pam.d setting on RHEL 5.7 and SuSe 11, and I was hoping to add more words into the current cracklib dict, so I use "echo" command to append new words into the file

I dont want to add the same words into the dict, I think I have too many redundant words now. I am using grep, but then grep is only going to show me so much, how do I find a word, sort it out alphabetically and pipe it to a file (that i can cross check so I dont end up adding same words into it)?

Code:

find /path/to/dir -name "itelli" <ok, im lost with sort,the only option i know is sort -nk and pipe> :(

Thanks!

---------- Post updated at 03:32 PM ---------- Previous update was at 03:22 PM ----------

Seems every time I post something here I get results on my own

Code:

find /path/to/dir -name "itelli" | sort -d >/tmp/words.txt

Another approach could be to check that the wanted password match some complexity enforced rules (with a minimum number of uppercase , char, figures, punct character and so on ...)

Hi HeadKandi,

A better answer would be as follows;

Code:

find /path/to/dir -name "itelli" | sort -du >/tmp/words.txt

As this will ensure that there are no duplicates in the file.

Regards

Dave