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Double variable substitution

 
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# 1  
Old 06-10-2012
Data Double variable substitution
Code:
$ ABCel='abc@gmail.com'
$ XYZel='xyz@gmail.com'
$ MYel='my@yahoo.com'

$ echo $ABCel
abc@gmail.com
$ echo $XYZel
xyz@gmail.com
$ echo $MYel
my@yahoo.com


I tried 3 variations, but not getting the expected result:

Code:
$ for VAR in ABC XYZ; do echo -e "${VAR}el $MYel"; done
ABCel my@yahoo.com
XYZel my@yahoo.com


Code:
$ for VAR in ABC XYZ; do MAIL=${VAR}el; echo -e "$MAIL $MYel"; done
ABCel my@yahoo.com
XYZel my@yahoo.com


Code:
$ for VAR in ABC XYZ; do MAIL=${VAR}el; echo -e "${MAIL} $MYel"; done
ABCel my@yahoo.com
XYZel my@yahoo.com

Expecting Result:
---------------------
Code:
abc@gmail.com my@yahoo.com
xyz@gmail.com my@yahoo.com

What am I missing here?
Thanks
Last edited by Scrutinizer; 06-10-2012 at 03:55 PM.. Reason: code tags
# 2  
Old 06-10-2012
Try this:eval echo \$${VAR}el
 
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