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Awk Help - toupper/tolower

 
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# 1  
Old 06-08-2012
Awk Help - toupper/tolower
Hi,

I am learning awk and faced few queries. Kindly suggest on the same. Where it is wrong.

Code:
$ awk '{if (toupper($1) ~ /a/) print $0}' inv 

$ awk '{if (toupper($1) ~ /A/) print $0}' inv -- Why this output
Jan  13  25  15 115
Mar  15  24  34 228
Apr  31  52  63 420
May  16  34  29 208
Aug  15  34  47 316
Jan  21  36  64 620
Mar  24  75  70 495
Apr  21  70  74 514

It should be like this.
Apr  31  52  63 420
Aug  15  34  47 316
Apr  21  70  74 514

$ awk '{if (tolower($1) ~ /A/) print $0}' inv

$ awk '{if (tolower($1) ~ /a/) print $0}' inv  ---why this output
Jan  13  25  15 115
Mar  15  24  34 228
Apr  31  52  63 420
May  16  34  29 208
Aug  15  34  47 316
Jan  21  36  64 620
Mar  24  75  70 495
Apr  21  70  74 514

It should be like this.
Jan  13  25  15 115
Mar  15  24  34 228
May  16  34  29 208
Jan  21  36  64 620
Mar  24  75  70 495

# 2  
Old 06-08-2012
toupper($1) ~ /A/ => If the first field (converted to uppercase) contains 'A' ""anywhere"" in the string.

Try this instead: toupper($1) ~ /^A/ to filter out the first field ""starting"" with 'A'

And, I'm not able to understand the second requirement. Do you want to search in first field if second character is 'a'?
Last edited by balajesuri; 06-08-2012 at 08:57 AM..
# 3  
Old 06-08-2012
Quote:
Originally Posted by balajesuri
toupper($1) ~ /A/ => If the first field (converted to uppercase) contains 'A' ""anywhere"" in the string.

Try this instead: toupper($1) ~ /^A/ to filter out the first field ""starting"" with 'A'

And, I'm not able to understand the second requirement. Do you want to search in first field if the second character is 'a'?
My concern is that in first case, it should pick "A" only not "a" irrespective of the position.

Code:
$ awk '{if (toupper($1) ~ /A/) print $0}' inv -- Why this output
Jan  13  25  15 115
Mar  15  24  34 228
Apr  31  52  63 420
May  16  34  29 208
Aug  15  34  47 316
Jan  21  36  64 620
Mar  24  75  70 495
Apr  21  70  74 514

It should be like this.
Apr  31  52  63 420
Aug  15  34  47 316
Apr  21  70  74 514

In second case, it should not pic "A" but "a"

Code:
$ awk '{if (tolower($1) ~ /a/) print $0}' inv  ---why this output
Jan  13  25  15 115
Mar  15  24  34 228
Apr  31  52  63 420
May  16  34  29 208
Aug  15  34  47 316
Jan  21  36  64 620
Mar  24  75  70 495
Apr  21  70  74 514

It should be like this.
Jan  13  25  15 115
Mar  15  24  34 228
May  16  34  29 208
Jan  21  36  64 620
Mar  24  75  70 495

# 4  
Old 06-08-2012
For first case, did you try this? toupper($1) ~ /^A/

For second case,
Code:
# awk 'toupper($1) !~ /^A/ && tolower($1) ~ /a/ {print}' inv
Jan  13  25  15 115
Mar  15  24  34 228
May  16  34  29 208
Jan  21  36  64 620
Mar  24  75  70 495

# 5  
Old 06-08-2012
toupper, tolower converts the argument to upper or lowercase...
So what was returned is what is expected...
# 6  
Old 06-08-2012
Quote:
Originally Posted by vbe
toupper, tolower converts the argument to upper or lowercase...
So what was returned is what is expected...
How it has returned what is expected. Using CYGWIN_NT-5.1

Code:
awk '{if (toupper($1) ~ /A/) print $0}' inv

Code:
Input file :

$ cat inv

Jan  13  25  15 115
Feb  15  32  24 226
Mar  15  24  34 228
Apr  31  52  63 420
May  16  34  29 208
Jun  31  42  75 492
Jul  24  34  67 436
Aug  15  34  47 316
Sep  13  55  37 277
Oct  29  54  68 525
Nov  20  87  82 577
Dec  17  35  61 401

Jan  21  36  64 620
Feb  26  58  80 652
Mar  24  75  70 495
Apr  21  70  74 514

Should return as under :

Code:
Apr  31  52  63 420
Aug  15  34  47 316
Apr  21  70  74 514

rest are unwanted like :
Code:
Jan  13  25  15 115
Mar  15  24  34 228
May  16  34  29 208
Jan  21  36  64 620
Mar  24  75  70 495

Last edited by Scrutinizer; 06-08-2012 at 09:48 AM.. Reason: additional code tags
# 7  
Old 06-08-2012
Then don't use toupper:
Code:
awk '$1~/^A/' inv

 
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