UNIX for Dummies Questions & Answers

Hi All,

I have a requirement where I need to first capture the current day & move all the files from a particular directory based on a previous day.

i.e move all the files from one directory to another based on current day & a previous day. Here is what I am trying, but it gives me errors.

Code:

export BUS_DATE=`cat path/filename.txt| grep 'P_BUS_DATE' | cut -d"=" -f2`
CURR_DY=`date "+%Y%m%d"`
CURR_DY_SECS=`date --date=$CURR_DY +"%s"`
BUS_DATE_SECS=`date --date=$BUS_DATE +"%s"`
DAYS=`$((($CURR_DY_SECS - $BUS_DATE_SECS) / 86400 ))`
echo $DAYS
i=$DAYS
while [ $i -ge 0 ]
  do 
 `mv /patha/filename.$(expr $CURR_DY - $i).dat /pathb/destination/`
  i=$ [ expr $i - 1 ]
done

Pls note the platform is LINUX.

Thanks much in advance,
Freddie

Hi,
may you please show the output of the running script and the output of cat path/filename.txt| grep 'P_BUS_DATE'?

Hi Frappa,

Here is the log I am seeing after executing the script.

++ grep P_BUS_DATE
++ cut -d= -f2
+ export BUS_DATE=20120528
+ BUS_DATE=20120528
++ date +%Y%m%d
+ CURR_DY=20120605
++ date --date=20120605 +%s
+ CURR_DY_SECS=1338872400
++ date --date=20120528 +%s
+ BUS_DATE_SECS=1338181200
++ 8
script.ksh: line 31: 8: command not found
+ DAYS=
+ i=
+ '$DAYS'
scripts.ksh: line 33: $DAYS: command not found
+ '[' -ge 0 ']'
scripts.ksh: line 34: [: -ge: unary operator expected

Can you pls shed some light.

Thanks Much
Freddie

---------- Post updated 06-06-12 at 12:28 PM ---------- Previous update was 06-05-12 at 03:52 PM ----------

Hi All,

I made some improvements in the issue below,

Here is the error I am getting now,

Any thoughts are appreciated

Thanks,
Freddie