Selecting the file of latest Date


 
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# 1  
Error Selecting the file of latest Date

Hi Folks,
I have one query that there is a folder in which daily several logs files are getting created , I reached to that location through putty but what I observer that 10 files of different date are been created with same name , what I need to see is the latest file ...let say the location is

cd /var/logs

at this location I see ten different files of different date with same name say abc.log , I want to see the abc.log file of the latest date before opening it in Vi , please advise me the command that will filter out the latest abc.log file of latest date, so That I can open the latest file through Vi editor
# 2  
You can't have ten files with the same name in a directory. Is the date embedded in the filename? If so, best is in the format YYYYMMDDHHmm, then the files will display already sorted.

Code:
vi $(tail -1 <(ls))

Otherwise
Code:
vi $(head -1 <(ls -t))

This User Gave Thanks to Scott For This Post:
# 3  
Quote:
Originally Posted by Scott
You can't have ten files with the same name in a directory. Is the date embedded in the filename? If so, best is in the format YYYYMMDDHHmm, then the files will display already sorted.

Code:
vi $(tail -1 <(ls))

Otherwise
Code:
vi $(head -1 <(ls -t))

Yeah scott , files are created with date is also embedded with them let say,
HTML Code:
abc20120515abc.log
abc20120516abc.log
abc20120517abc.log
so please advise I want to open the latest one through Vi editor abc20120517abc.log file
# 4  
Code:
vi $(tail -1 <(ls abc*.log))

Or if <(..) doesn't work
Code:
vi $(ls abc*.log | tail -1)

Otherwise
Code:
set -- abc*.log
vi $(eval echo \${$#})

# 5  
you will get the latest file name : ls -lrt | tail -1then vi it.

Last edited by Scott; 05-19-2012 at 01:35 PM.. Reason: Code tags
# 6  
Code:
vi $(ls -t abc*.log | head -1)


Last edited by Scott; 05-19-2012 at 01:35 PM.. Reason: Code tags
 

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