UNIX for Dummies Questions & Answers

 
expr `20121231 +%Y%m%d` + 1

$ ./inc.pl 1999-12-31
2000-01-01
jim@jim-HP ~
$ ./inc.pl 2011-12-31
2012-01-01
jim@jim-HP ~
$ ./inc.pl 2010-02-28
2010-03-01
jim@jim-HP ~
$ ./inc.pl 2012-02-28
2012-02-29

#!/bin/bash
# inc.pl - from a perl script....

inc_date()   # add 86400 seconds to time in seconds from date to get the next day
{
  declare -a arr=( $(echo "$1" | tr -s '-' ' ') )
 
  perl -e  '     
         use Time::Local;            
         $time = timelocal(0,0,0, $ARGV[0], $ARGV[1] -1, $ARGV[2] );
         $time+=86400;  # one day = 86400 seconds
         ($sec,$min,$hour,$mday,$mon,$year,$wday,$yday,$isdst)=localtime($time);
         $year+=1900;
         $mon+=1;         
         printf "%d-%02d-%02d\n", $year, $mon, $mday;
         ' ${arr[2]} ${arr[1]} ${arr[0]}
}

inc_date "$1"

perl -e 'printf "%s\n", scalar localtime(time() + 86400)'

 
data/test>inc.pl 2012-12-12

 
# inc.pl - from a perl script....
inc_date()   # add 86400 seconds to time in seconds from date to get the next day
{
  declare -a arr=( ./inc.pl[2]: syntax error at line 8 : `(' unexpected