UNIX for Dummies Questions & Answers

Hi,

I have hundred folders under a fs /apps which is used by different users and they upload their data to these folders on a daily basis.
Using du -sk gives me complete structure of the filesystem but i want to find out day to day utlization of the top ten highest accoriding to size wise


example...

A filesystem /apps under which there are more than 100 sub folders. I need output of the top 10 as per size on a daily basis

/apps/folder1
/apps/folder2
/apps/folder3
/apps/folder4
/apps/folder5
....
....
...
....
/apps/folder99
/apps/folder100

This may help using shell script.

Code:

du -k apps > temp
sed '$d' temp > temp1
mv temp1 temp
awk '$1>max {max=$1;val=$2} END {print max, val}' temp

Code:

du -sk /apps/* | sort -n -r | head -10

Thanks methyl for the correction, i missed the top 10 part.
Just a change in your one liner

Code:

du -k apps | sed '$d' | sort -nr | head -10

-sk will give the total sum, sed to delete the total sum at the end.

Thanks friend, i'll try these at my test servers and also i want to direct the output of this to a file so that i can send report to the client automatically by using send mail service.