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sed, join lines that do not match pattern

 
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# 1  
Old 04-30-2012
sed, join lines that do not match pattern
Hello,
Could someone help me with sed. I have searched for solution 5 days allready Smilie, but cant find. Unfortunately my "sed" knowledge not good enough to manage it. I have the text:
Code:
123, foo1, bar1, short text1, dat1e, stable_pattern
124, foo2, bar2, long text
with few
lines, date, stable_pattern
125, foo3, bar3, short text2, date, stable_pattern

I need 1 string per record. So, 124 record should be ammended and all its lines should be joined in one. Output should be:
Code:
123,foo, bar,short text,date,stable_pattern
124,foo2, bar2, long text with few lines,date, stable_pattern
125,foo3,bar3,short text, date, stable_pattern

Actually i need to join lines that do not match pattern. In this sample pattern is "stable_pattern". I "construct" Smilie the following command, but it does not work:
Code:
cat text|sed -e '/stable_patter/!s/$//'

Seams the way is correct, but it does not remove the |new line| symbol:
Code:
 cat text|sed -e '/stable_patter/!s/$/_______sould_be_removed_____/'
123, foo1, bar1, short text1, dat1e, stable_pattern
124, foo2, bar2, long text_______sould_be_removed_____
with few_______sould_be_removed_____
lines, date, stable_pattern
125, foo3, bar3, short text2, date, stable_pattern


Somewhere on the internet i found another example, but it does not work for me too:
Code:
cat text|sed -e ":a;N;/stable_pattern/!s/\n//g;ta"
123, foo1, bar1, short text1, dat1e, stable_pattern
124, foo2, bar2, long text
with few
lines, date, stable_pattern
125, foo3, bar3, short text2, date, stable_pattern

Please help me to figure out this

thanks.
Last edited by petrasl; 04-30-2012 at 08:38 AM..
# 2  
Old 04-30-2012
I would use awk (nawk on Solaris):
Code:
awk '/stable_pattern$/ {print;next;} {printf("%s",$0);}' text

# 3  
Old 04-30-2012
You are my hero !!! Smilie Smilie
# 4  
Old 05-02-2012
sed, join lines that do not match pattern
Hi jlliagre,

great can you please explain this awk completly how it works here in joining lines.
Code:
awk '/stable_pattern$/ {print;next;} {printf("%s",$0);}' text

I am confuse for
Code:
next

stmt and other
Code:
printf

how it is joinging if search fails for a line.

Thanks
Krsnadasa
# 5  
Old 05-02-2012
Here are some explanations:next is skipping the remaining rule(s).

print is equivalent to printf("%s\n",$0)

printf format string doesn't specify a new line (no tailing \n), so the next line(s) are joined.
 
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