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Deleting files based on Substring match

 
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# 8  
Old 04-18-2012
ls $FILE | grep -v "$UPPDATE" will list files other than todays date check -v option of grep.
Other alternative to delete such files is
Code:
find $FILE -maxdepth 1 ! -name \*"$UPPDATE"* -exec rm {} \;

Last edited by 47shailesh; 04-18-2012 at 02:54 PM.. Reason: changed . to $FILE to look in a that directory
This User Gave Thanks to 47shailesh For This Post:
manushi88
# 9  
Old 04-18-2012
Quote:
This is listing all the files not having today's date timestamp. Now I have to delete the files which are listed .Kindly help me out how I can delete the files.
Code:
#!/bin/ksh

DATE=`date +"%d%h%Y"`
DIR="/data/rfs/"
FOLDER="Test"
TARGET="${DIR}${FOLDER}"

UDATE="$(echo $DATE | tr '[a-z]' '[A-Z]')"

ls "${TARGET}" 2>/dev/null | grep -v "${UDATE}" | while read FILENAME
do
         # Remove echo when tested
         echo rm "${FILENAME}"
done
exit 0

Last edited by methyl; 04-18-2012 at 01:45 PM.. Reason: make variable same case as rest of script. change name of $FILE to $TARGET (it isn't a file). allow for no files
This User Gave Thanks to methyl For This Post:
manushi88
# 10  
Old 04-19-2012
HI,

Thanks to all for your valuable and helpful suggestions
 
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