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how to print the column that contains a string in delimited file in unix

 
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# 1  
Old 04-04-2012
how to print the column that contains a string in delimited file in unix
Hi Team,

I have a requirement to print the column or find the column number of a particular string in delimited (Smilie file.

Ex:

Code:
aaa;bbb;ccc;rrr;mmm;
gggg;rrr;mmmm;ssss;eee;aaa;
ccc;gggg;tttt;bbbb;dddd;ggggg;rrr;

my file contains 1000+ rows like above example with semicolon delimited. i need to take string 'rrr' column in each row.



Please help me on this.

thanks,
Baski
Last edited by Scrutinizer; 04-04-2012 at 03:57 AM.. Reason: Code tags...
# 2  
Old 04-04-2012
Code:
awk -F";" '{for(i=1;i<=NF;i++){if ($i ~ /rrr/){print i}}}' filename

# 3  
Old 04-04-2012
Hi ningy,
small change in your solution

Code:
awk -F";" '{for(i=1;i<=NF;i++){if ($i ~ /rrr/){print $i}}}' FileName

Regards,
Shanmu

---------- Post updated at 11:33 AM ---------- Previous update was at 11:31 AM ----------

Hi baskivs,

Try this also,

Code:
sed 's/\(.*\)\;\(rrr\)\;\(.*\)/\2/g' FileName

Regards,
Shanmu
# 4  
Old 04-04-2012
Hi ningy,
small change in your solution

Code:
awk -F";" '{for(i=1;i<=NF;i++){if ($i ~ /rrr/){print $i}}}' FileName

Regards,
Shanmu

---------- Post updated at 11:33 AM ---------- Previous update was at 11:31 AM ----------

your change is wroong if u use $i it will print rrr..
 
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