Remove files by name

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# 1  
Old 03-26-2012
Remove files by name

I have multiple xml files and named

and I want to delete or to remove only these with the hightest ID e.g. files 1234__AAA__12.xml and 2127__AAA__13.xml.

Could you tell me how can i do that? Is there any script?

Thank you for your help!
Moderator's Comments:
Mod Comment please use code tags
# 2  
Old 03-27-2012
Here is one way of doing it:
sed 's/.*\(__.*__.*\).xml/\1/' Inp_File | uniq | while read mStr; do
  grep "${mStr}" Inp_File | sort -t_ -k3 -kn1 | tail -1

# 3  
Old 03-27-2012
You can perform a sort on the first number. Check for a cutoff number and remove all the files from then onwards.
# 4  
Old 03-28-2012
We all know what must be done.

The issue is how to do it.

Please, provide your solution using actual unix commands.
# 5  
Old 03-28-2012
The following will give the files whose first numbers exceed 1250.

echo "1233__AAA__12.xml 1234__AAA__12.xml 2125__AAA__13.xml" | tr ' ' '\n' | awk 'BEGIN{FS="_"}{if ($1 > 1250) {print}}'

---------- Post updated at 11:03 AM ---------- Previous update was at 10:59 AM ----------

This will give you the command to run in a file which I call

ls -lrt *.xml | awk '{print $NF}' | awk 'BEGIN{FS="_"}{if ($1 > 1250) {print "rm "$0}}' >

Last edited by kristinu; 03-28-2012 at 02:15 PM..
# 6  
Old 03-29-2012
given the short sample list of files and desired selection, I guess your definition of "highest ID" is the leftmost portion of the filename preceding the fourth underscore? You'll have to hack on this code to adjust if I am misunderstand your filename pattern.

for i in $(ls -1 *.xml | cut -d\. -f1 | cut -d_ -f5 | sort -u); do ls -1 *${i}.xml | tail -1; done

if that code snippet produces the correct list of files, then just tack on a 'xargs rm' to do the dirty work. e.g.

... tail -1; done | xargs rm -f

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