UNIX for Dummies Questions & Answers

Hello,

I have a script to get the information from database, however, it's look like the loop is not work, can someone help?

echo Input file list to check:
read filelist
for file in 'cat $filelist.txt'
do
echo "select FILENAME from FILE_TABLE where filename like '${file}'%;" >> output_file.txt
done
echo Completed Check!!


The filelist is:
list1
A1-67630403
A2-04985959
B3-04857858
B6-058744748
C10-59584583

Single-quotes is the problem here. It should be backticks, like this:

Code:

for file in `cat $filelist.txt`

This method is not so good owing to useless use of cat. You can try the below method:

Code:

while read file
do
...
done < ${filelist}.txt

Also, I'm no expert at SQL, but shouldn't the echo statement be like this? (% with-in the single quotes)

Code:

echo "select FILENAME from FILE_TABLE where filename like '${file}%';"

sorry about the typing mistake, the % should be removed, like this

echo "select FILENAME from FILE_TABLE where filename like '${file}';"

Also, I used backticks in unix, still not work :-(

Please post the script you used.

I am tried to use your suggested while, is not work

What does not work? Do you see an errormessage or do you get wrong results? What shell, OS and database-system are you using?
About the SQL-syntax: its either filename = \'${file}\' looking for exact matches or filename like \'${file}%\' looking for values that start with those strings.

@happyv: We won't be able to help unless you provide more inputs.