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Remove the date portion from file name

 
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# 1  
Old 02-14-2012
Remove the date portion from file name
hi,
I am trying to remove the last field before the period (.) from a list of file names in a directory in a shell script.
Below is the list of file names.

PHP Code:
ENVID_archival_20120214092258.log            
ENVID_Get_Source_Files_20120214091828.log  
ENVID_Get_Source_Files_20120214092523.log
ENVID_email_notification_20120214091829.log  
ENVID_Get_Source_Files_20120214092026.log 
_ and the date part followed by it have to be removed and the result should be:
PHP Code:
ENVID_archival.log            
ENVID_Get_Source_Files.log  
ENVID_Get_Source_Files.log
ENVID_email_notification.log  
ENVID_Get_Source_Files.log 
I tried with cut. But as the date field position is dynamic, I could not get it through successfully. can some one help?

thanks
# 2  
Old 02-14-2012
Code:
perl -pe 's/_\d+//' file

# 3  
Old 02-14-2012
Hi bartus11, I am doing a unix script.. and I would like to do this in the script with shell commands..(bash) in my unix script.. My system is Linux.
# 4  
Old 02-14-2012
Code:
$ f=ENVID_Get_Source_Files_20120214092523.log
$ echo "${f%_*}.${f##*.}"
ENVID_Get_Source_Files.log

# 5  
Old 02-14-2012
Hi Scrutinizer, thanks for your quick response.. can you please explain me what is "${f%_*}.${f##*.}" ??
I am quite new in unix, please explain.
# 6  
Old 02-14-2012
Hi Vijay, this is called parameter expansion.
These 3 Users Gave Thanks to Scrutinizer For This Post:
daWonderer Vijay81 vishal_vsh1
# 7  
Old 02-15-2012
Scrutinizer, this was great. Thanks for the link, it is even useful to me in many cases.
 
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