Sleep Until Query


 
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# 1  
Old 01-13-2012
CPU & Memory Sleep Until Query

Hi,
I am a newbie in UNIX

please help me develop code for below logic:--

I want my script to implement sleep until a specified time(date doesn't matter)

----------------------------------------
While currenttime > 14:00 and < 18:00
sleep
end while

run command

exit
-----------------------------------------
basically i want my script to run if it is not between 2PM and 6PM.
Else command should run when ever invoked.

Appreciate all help.

Regards,
Kit
# 2  
Old 01-13-2012
Hint:
Look at this command to find the current time in 24-hour clock format with leading zeros on the numbers:
Code:
date +%R

# 3  
Old 01-13-2012
Quote:
Originally Posted by methyl
Hint:
Look at this command to find the current time in 24-hour clock format with leading zeros on the numbers:
Code:
date +%R

Hi Methy,
thanks for the quick response.

Lets assume i assign x=echo `date +%R`
and it populates x=1:32

How do I compare that value with a variable containing value for 02:00PM?
I mean can i say x > y
where x=1:32 and y=02:00

Also how do i get x=13:32 instead of 1:32 by using date + %R
# 4  
Old 01-13-2012
Hi kiitmale,

Code:
man date

lists all available date format specifications;

in your case
Code:
date '+%H:%M'

should do the trick (but read man date as the implementation of date on a commercial unix system may be different).

The variable that stores the date may be assigned just as:
Code:
x=`date '+%H:%M'`

then the strings ascii comparison may be done:
Code:
if [ "${x}" \> "${y}" } ; then
   # ...something
else
   # ...something
fi

remember to escape string disequality operatpors with a backslash.

you may also see Other Comparison Operators

see ya
fra
# 5  
Old 01-13-2012
CPU & Memory my attempt till now

hi,
I tried as below:


Code:
#!/bin/ksh
##check current time
curr_time=`date +%H%M`
# SET and Initialize Time variables
time7pm=1600
time0630am=1620  ##assume currtime was 1615
echo $curr_time
echo $time7pm
while [ $curr_time -ge $time7pm and $curr_time -le $time630am ]
do
                curr_time=`date +%H%M`
                echo $curr_time
                sleep 10
done
curr_time=`date +%H%M`
echo "outside loop"
echo $curr_time 
exit 0

Somehow code nevers escapes the while Loop.
Any pointers?

Last edited by methyl; 01-14-2012 at 05:15 PM.. Reason: please use code tags
# 6  
Old 01-13-2012
You might find the whole process easier if you set it up as a cron job.
Take your original script and have it process one iteration then quit.
Add a cron entry to run once a minute Monday to Friday? for 00 to 13 (the last run is 13:59) and 18 to 23
Quote:
The crontabs files consist of lines of six fields each. The
fields are separated by spaces or tabs. The first five are
integer patterns that specify the minute (0-59), hour (0-23), day
of the month (1-31), month of the year (1-12), and day of the
week (0-6, with 0=Sunday). Each of these patterns may contain:
Code:
1-59     0-13,18-23   *    *   1-5    myscript

# 7  
Old 01-13-2012
cannot use cron job

Quote:
Originally Posted by jgt
You might find the whole process easier if you set it up as a cron job.
Take your original script and have it process one iteration then quit.
Add a cron entry to run once a minute Monday to Friday? for 00 to 13 (the last run is 13:59) and 18 to 23
Code:
1-59     0-13,18-23   *    *   1-5    myscript

Unfortunately for my requirements i cannot use cron job.
Please let me know if you can spot any issues with my code in previous post.
 
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