I am trying to print a listing of files from the top level directory, check to see if any files have the same name as the top level directory name and if so, cd to that file and list the files under it. Don't know how to check for the file in the next level.
What I have so far:
Code:
#/usr/bin/ksh!
#Usage: ksh search.ksh directory_name
rm -f cat_report.dat
cd $1
pwd
echo "Directory is $1" >> /apps/system_admin/scripts/cat_report.dat
ls -l >> /apps/system_admin/scripts/cat_report.dat
while [[ -d $1 ]];
do
echo "Directory $1 does exist in $(pwd)" >> /apps/system_admin/scripts/cat_report.dat
check to see if any files have the same name as the top level directory name and if so, cd to that file and list the files under it.
Sorry, don't understand this. You cannot "cd" to a file, you can only "cd" to a directory. Are you actually looking for duplicate directory names?
Can you give an example?
Sorry, yes you are right. I would be doing a 'cd' to a directory under the current one with the same name.
Ex:
Mount point name - /cat
cd /cat
List directories under /cat using ls -l
cat
dog
fish
Find another directory called cat
cd to that directory and list the directories
cd cat
ls -l
keep checking until a directory called cat is not found.
find "/cat" -xdev -type d -name "cat" -print | sort | while read dir
do
echo "${dir}"
cd "${dir}"
ls -ld * | grep \^\d # Directories only
echo ""
done
Hard to understand your requirement. Not clear whether you are suggesting using "ls" (not "find") to locate the directory or whether you actually want to display the output. I guessed the latter. Note the use of "ls -ld *" to avoid "ls" listing the contents of subdirectories.
find "/cat" -xdev -type d -name "cat" -print | sort | while read dir
do
echo "${dir}"
cd "${dir}"
ls -ld * | grep \^\d # Directories only
echo ""
done
Hard to understand your requirement. Not clear whether you are suggesting using "ls" (not "find") to locate the directory or whether you actually want to display the output. I guessed the latter. Note the use of "ls -ld *" to avoid "ls" listing the contents of subdirectories.
Thanks, I'll give this a try. Yes, I need to get an actual listing of all of the directories at each level as long as the criteria of finding the same directory name in each. Once the directory does not have any other directories with the same name as the one previous it is complete.
ex: /cat - top level
ls -ld - shows the following directories; cat, dog, fish
Because cat is listed, cd cat
ls -ld - shows the following directories; cat, horse, duck
Again, cat is listed so 'cd cat'
ls -ld - shows the following directores; bird, turtle, snake
No 'cat' listed so completes.
Hope this helps to clarify.
---------- Post updated at 10:26 AM ---------- Previous update was at 10:12 AM ----------
Quote:
Originally Posted by methyl
Something similar to this?
Code:
find "/cat" -xdev -type d -name "cat" -print | sort | while read dir
do
echo "${dir}"
cd "${dir}"
ls -ld * | grep \^\d # Directories only
echo ""
done
Hard to understand your requirement. Not clear whether you are suggesting using "ls" (not "find") to locate the directory or whether you actually want to display the output. I guessed the latter. Note the use of "ls -ld *" to avoid "ls" listing the contents of subdirectories.
Helo
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A_START_PATH="/data_1/data_2"
#
# dir2, dir3, dir6, ..... dir59 exists
#
A_LIST="$A_START_PATH/dir1 $A_START_PATH/dir4 $A_START_PATH/dir5"
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12-30-2011
