UNIX for Dummies Questions & Answers

I have a pattern for filename to be searched.
I need to get the files from remote server Who are matching the file pattern.
And i need to exit with non zero return code for:

1)No files found matching that pattern

2)More than one files matching the name pattern.

If only one files is matching, then exit with zero return code.

Currently i am doing like in the below script:

Code:

ftp -in server<<EOF
user username pwd
cd $tgtdir
mget  Filepattern
quit
bye
EOF

if [ $? -ne 0 ]
then
echo "there are some issues in FTP"
fi

cd $localpath
ls Filepattern

if [ $? -eq 2 ]
then
echo "File not found"
exit 3
else
echo "File transfer success"
fi

cnt=`ls filepattern|wc -l`

if [ cnt -gt 1 ]
then
echo "More than one file"
exit 2
else
echo "Only one file"
exit 0
fi

But i dont think , the above is not the good approach and that may lead to ugly false negatives in some cases.

Please suggest me, how i can achieve this.

Thanks

Why not capture ftp's output to see what files it retrieved?

Code:

ftp -in server >logfile 2>&1 <<EOF
user username pwd
cd $tgtdir
mget  Filepattern
quit
bye
EOF

How to process logfile depends on what its output actually is of course. FTP on my system probably doesn't look much like FTP on yours. Post a sample and we can help.