how to count number of times each word exist in a file


 
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# 1  
Old 12-06-2011
Question how to count number of times each word exist in a file

I'm trying to count the number of times each word in the file exist
for example if the file has:
today I have a lot to write, but I will not go for it. The main thing is that today I am looking for a way to get each word in this file with a word count after it specifying that this word has occured that number of times in the whole file.

today-->2
I-->3
have-->1
a-->3
lot-->1
write-->1
but-->1
will-->1
not-->1


and so on


I used tr to separate each word in a line but I'm not sure how I'm going to look for each word
# 2  
Old 12-06-2011
Try
Code:
 tr ' ' '\12' <inputfile| sort | uniq -c | sort -nr

The output looks like
Code:
      3 word
      3 that
      3 I
      3 a
      2 today
      2 to
      2 this
      2 in
      2 for
      1 write,
      1 with
      1 will
...

This User Gave Thanks to hergp For This Post:
# 3  
Old 12-06-2011
echo "1 2 3 3 2 1" | xargs -n 1 | awk '{a[$0]++} END{for(i in a) {print i , a[i]} }'
This User Gave Thanks to tarun_agrawal For This Post:
# 4  
Old 12-06-2011
counting not correct yet

that helps a lot
but when I run it on a big file, it repeats the word
like if I have the words
bad, bad. bad: bad,
it will show
2 bad,
1 bad.
1 bad:
I only want to count the word itself so I have to delete punctuation to get it right I guess
by the way what is /12 stand for???

Quote:
Originally Posted by hergp
Try
Code:
 tr ' ' '\12' <inputfile| sort | uniq -c | sort -nr

The output looks like
Code:
      3 word
      3 that
      3 I
      3 a
      2 today
      2 to
      2 this
      2 in
      2 for
      1 write,
      1 with
      1 will
...

---------- Post updated at 06:03 PM ---------- Previous update was at 05:59 PM ----------

---------- Post updated at 06:07 PM ---------- Previous update was at 06:03 PM ----------

I couldn't implement this on what I've
I don't understand the logic behind this code
which I don't know where to add the file that I'm suppose to count the words in it

Smilie

Quote:
Originally Posted by tarun_agrawal
echo "1 2 3 3 2 1" | xargs -n 1 | awk '{a[$0]++} END{for(i in a) {print i , a[i]} }'
# 5  
Old 12-07-2011
Bug

you could change everything to lower-case and remove any non-letters characters to make it more accurate.

Code:
tr ' ' '\12' <inputfile | tr 'A-Z' 'a-z' | sed s/[^a-zA-Z]//g | sort | uniq -c | sort -nr

 
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