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[Solved] take name of directory and files as variables
11-21-2011
11-21-2011
cp * /new/direcotry
echo " file one (name of file ) has been copied "
echo " file two ( name of file )has been copied " etc
vi sample0001
#!/bin/sh -x
echo "======================"
echo " Start of sample0001 "
echo "======================"
dir=~/Documents/Scripts/Copy
for i in $(pwd) $(ls)
do
echo "$i"
if [ -d $dir ]; then
echo "\$2: " $2
echo "idr : " $dir
cp $2 $dir
echo " $2 copied to directory $dir "
else
mkdir Copy && cp $2 $dir
echo "line 18 - $2 copied to directory $dir "
fi
echo next
read kyb
done
11-21-2011
#!/bin/bash
dir="/home/andre/Documents/Scripts/Copy/"
FILE=(ls)
for i in $FILE
do
cp -i "$1" "${dir}${1}"
echo " file $1 has been copied to $dir "
cp -i $3 $dir $3
echo " file $2 has been copied to $dir "
cp -i $4 $dir $4
echo " file $3 has been copied to $dir "
done
done
for i in $(pwd) $(ls)
do
echo "$i"
if [ -d $dir ]; then
cp -a * ~/Documents/Scripts/Copy #these would copy all files to Copy dir
echo " files copied to directory $dir "
else
mkdir Copy && cp $i $dir
echo " $2 copied to directory $dir "
end
I am getting nowhere so far, to bad I missed your replies because would be helpful to chat with someone like you while doing....
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