copy files grabbing destination folder from file name


 
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# 1  
copy files grabbing destination folder from file name

Hi all...

Below is what I am trying to do:
1. Having the following folder with the files...
/source_folder/dodiddone.tar.gz
/source_folder/gowentgone.tar.gz
/source_folder/gowentgone.log

2. I need to copy and chown files with extension .tar.gz to another folder
copy /source_folder/dodiddone.tar.gz /dodiddone/destiny_folder/dodiddone.tar.gz
copy /source_folder/gowentgone.tar.gz /gowentgone/destiny_folder/gowentgone.tar.gz

3. code
#!/bin/sh
SOURCE="/source_folder"
EXTENSION="tar.gz"

for i in "$SOURCE"/*.$EXTENSION
do
copy $i /(???-1-)/(???-1-).$EXTENSION
chown /(???-1-)/(???-1-).$EXTENSION
done

4. my doubts!
(???-1-) : here would be something like ${i%%.$EXTENSION} |sed 's#^.*/##' to grab the file name

***
Could you please help to solve this problem?

Many thanks!!!

Last edited by pedroz; 11-12-2011 at 12:00 PM..
# 2  
This is probably pretty close to what you're looking for:

Code:
extent=tar.gz
srcd=/tmp/test
for i in $srcd/*.$extent
do
    fname=${i##*/}      # without path
    fwoe=${fname%.$extent}  # without path or extension
    dest=/$fwoe/$fname     # set dest filename once
    echo cp $i $dest            # test with echo
    echo chown xxx $dest
done


Last edited by agama; 11-12-2011 at 02:29 PM.. Reason: typo
 

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