UNIX for Dummies Questions & Answers

My file looks something like this:

infile.seq
I need to include the filename in each identifier, without the extension, and number them with consecutive numbers starting with 1. So, the expected outfile should look like this:

I have been trying to modify the following code but I cannot get it to do exactly what I want.

Code:

awk '/\>/{F=$2; N=$3; getline}{print ">"FILENAME++" "F" " N"\n" $0}' infile.seq

Any help will be greatly appreciated!

FILENAME is a special variable and already set, incrementing it won't tag a "1" on the end.

How about FILENAME "." N++

Is there any way I can only include the filename without the extension?
This is the expected outfile:

Thanks!

Code:

split(FILENAME, A, ".");
print ... > A[1] "-" N++;

---------- Post updated at 10:01 AM ---------- Previous update was at 10:00 AM ----------

That might create FILE- instead of FILE-0... Hmm

Code:

split(FILENAME, A, ".");
print ... > A[1] "-" ++N;

This will create FILE-1, FILE-2, ... instead of FILE-, FILE-1, ...

Code:

 myprefix=FILENAME; sub ("....$", "", myprefix);

Got it!

Code:

awk '/\>/{F=$2; N=$3;split(FILENAME, A, "."); getline}{print ">" A[1]"-"N++" "F" " N"\n" $0}' infile.seq

Thanks!