For loop help


 
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# 1  
Old 09-26-2011
For loop help

Hi all ,

I have a simple script to get the file name and creation date
Code:
#! /bin/ksh 
 
for ifile in `ls -ltr |  awk -F " " '{print $6 , "#" , $7 , "#" , $8 ,  "#" , $NF}'`
do 
   echo ${ifile}
done

expected output
Code:
 
Sep # 10 # 00:00 # file_1

but it is coming as
Code:
#
Sep
#
10
#
00:00
#
file_1

Instead of printing row by row it print seprated by spaces Smilie
TIA


Found the solution

---------- Post updated at 12:58 AM ---------- Previous update was at 12:39 AM ----------

Find the solution Smilie

Code:
#! /bin/ksh
ls -ltr | awk -F " " '{print $6 , "#" , $7 , "#" , $8 ,  "#" , $NF}' | while read LINE
do
echo "${LINE}"
done


Last edited by max_hammer; 09-26-2011 at 03:57 AM..
# 2  
Old 09-26-2011
Code:
ls -ltr | awk -F " " '{print $6 , "#" , $7 , "#" , $8 ,  "#" , $NF}'

is enough.
# 3  
Old 09-26-2011
No need to mention the field seperator as space

The highlighted part is not needed

Code:
 
ls -ltr | awk -F " " '{print $6 , "#" , $7 , "#" , $8 ,  "#" , $NF}'

# 4  
Old 09-26-2011
Or just:
Code:
ls -ltr | awk '{print $6,$7,$8,$NF}' OFS=" # "

 
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