UNIX for Dummies Questions & Answers

There are two similar directory structures existing, e.g. old/ and new/, where
old/d1/d2/d4/, old/d1/d2/d5/, old/d1/d3/d6/ and old/d1/d3/d7 contains some files and now I want to move those files from each folder to new locations new/d1/d2/d4/, new/d1/d2/d5/, new/d1/d3/d6/ and new/d1/d3/d6/.

The files should be moved in batches, and in scheduled manner, i.e. 5 files from each directory to another one in every 10 minutes.

Kindly suggest the way forward, one can create and use additional files.

My approach: I created a file (say f1) containing all the filenames in old directory (by using find) and then a copy of f1, where I replaced "old/" by "new/" to get new paths for filenames, and tried to execute the move command by reading one by one from the two files, but I am not able to acheive how to manage 5 files from each directory].

Thanks.

try this ..

Code:

while [ 1 ]
do
        for i in old/d1/d2/d4 old/d1/d2/d5 old/d1/d3/d6 old/d1/d3/d7 
        do
        find $i -type f -print | tail -5 | sed p | paste - - | sed 's,old/,new/,2'| awk '{print "mv "$0}' | sh
        done
        sleep 600
done