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Grep bunch of gzip files to count based on category


 
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# 1  
Grep bunch of gzip files to count based on category

Started using unix commands recently.
I have 50 gzip files. I want to grep each of these files for a line count based particular category in column 3. How can I do that?

For example
Code:
Sr.No Date    City Description  Code  Address
1       06/09   NY  living here   0909  10st st nyc
2       07/09   NY    not here     1312   11 st st nyc
3       03.09    DC     gone          1321   232 st DC

I want to count all the cities for each of the 50 files. how do I do that?
Also want to output the city count for each of the file.

Last edited by Franklin52; 09-14-2011 at 04:05 AM.. Reason: Please use code tags for code and data samples, thank you
# 2  
See if this will help you:
Code:
#!/usr/bin/ksh
cut -d' ' -f3 Inp_File | sort -u |
while read mCity; do
  mTot=$(grep -c ${mCity} Inp_File)
  echo "City ${mCity} count ${mTot}"
done

# 3  
Code:
cd /path/to/gzfiles
for fname in *.gz
do
  echo "$fname ---------"
  gzcat $fname | awk ' {arr[$]++} ; END{for (i in arr) {print i, arr[i]   } }
  echo " "
done  > outputfile.txt

# 4  
Shell_life, I just forgot to mention there is no header in the file. That was just an example.Can this be represented in the form of column?

Last edited by jinxx; 09-12-2011 at 05:47 PM.. Reason: incorrect info
# 5  
Code:
$ for i in *.gz;do echo $i;gzip -dc $i | awk '{print $3|"sort"}'|uniq -c; done

This User Gave Thanks to jayan_jay For This Post:
# 6  
Thanks people!
 

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