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# 1  
Old 09-06-2011
Question List and grep
Hi,

My requirement is to copy all yesterdays files which have "access" keyword in their filenames to a separate folder say "/tmp/moht".

Can you please let me know how?
# 2  
Old 09-06-2011
What did you try so far?
# 3  
Old 09-06-2011
Question
Code:
ls -ltr
total 55472
-rw-r--r--   1 admin grp   1684877 Sep  2 20:47 51.error_log_443.201109020000.gz
-rw-r--r--   1 admin grp   26619984 Sep  2 20:48 51.access_log_443.201109020000.gz
-rw-r--r--   1 admin grp     58415 Sep  5 08:07 51.access_log_443.201109050000
-rw-r--r--   1 admin grp     17181 Sep  6 06:51 51.access_log_443.201109060000

Desired output:
Code:
-rw-r--r--   1 admin grp   26619984 Sep  2 20:48 51.access_log_443.201109020000.gz
-rw-r--r--   1 admin grp     58415 Sep  5 08:07 51.access_log_443.201109050000

My output:

Code:
find /apps/logs/ -mtime +1 -exec ls -ltr {} \;
-rw-r--r--   1 admin grp   1684877 Sep  2 20:47 /apps/logs/colweb-perf-0551.error_log_443.201109020000.gz
-rw-r--r--   1 admin grp   26619984 Sep  2 20:48 /apps/logs/51.access_log_443.201109020000.gz

Code:
date
Tue Sep  6 06:54:50 EDT 2011

Post correct filtering I am not even sure how to append the copy command so the output files gets copied to a different folder. I guess xargs may help.

I did not post this prior for i thought i may be misleading those who have better idea.

Regards,
# 4  
Old 09-06-2011
+1 means more than 24 hours ago.
Which operating system are you using?
# 5  
Old 09-06-2011
Question
Yes, thats what i am not sure, how to specify find so that it filters logs of the previous day rather than 24 hrs.

SunOS mymachine 5.10 Generic_144488-07 sun4v sparc SUNW,SPARC-Enterprise-T5220
# 6  
Old 09-06-2011
try this ..
Code:
#!/bin/bash
yest_dat_mon=`TZ=CST+24 date +%b`
yest_dat_day=`TZ=CST+24 date +%d | sed 's,^0,,g'`
if [ "$yest_dat_day" -lt 10 ]
then
        ls -ltr|grep " $yest_dat_mon  $yest_dat_day "|grep "access"|awk '{print "cp -p "$9" /tmp/moht"}' | sh
else
        ls -ltr|grep " $yest_dat_mon $yest_dat_day "|grep "access"|awk '{print "cp -p "$9" /tmp/moht"}' | sh
fi

This User Gave Thanks to jayan_jay For This Post:
shifahim
# 7  
Old 09-06-2011
Question
Quote:
Originally Posted by jayan_jay
try this ..
Code:
#!/bin/bash
yest_dat_mon=`TZ=CST+24 date +%b`
yest_dat_day=`TZ=CST+24 date +%d | sed 's,^0,,g'`
if [ "$yest_dat_day" -lt 10 ]
then
        ls -ltr|grep " $yest_dat_mon  $yest_dat_day "|grep "access"|awk '{print "cp -p "$9" /tmp/moht"}' | sh
else
        ls -ltr|grep " $yest_dat_mon $yest_dat_day "|grep "access"|awk '{print "cp -p "$9" /tmp/moht"}' | sh
fi


yest_dat_day=`TZ=CST+24 date +%d | sed 's,^0,,g'` return "5" for me. So what is the significance of "$yest_dat_day" -lt 10 ??

Can you please explain?

Also i do not see any difference in the if else statements i.e.

then
ls -ltr|grep " $yest_dat_mon $yest_dat_day "|grep "access"|awk '{print "cp -p "$9" /tmp/moht"}' | sh
else
ls -ltr|grep " $yest_dat_mon $yest_dat_day "|grep "access"|awk '{print "cp -p "$9" /tmp/moht"}' | sh

Please let me know.
Last edited by shifahim; 09-06-2011 at 10:42 AM..
 
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