UNIX for Dummies Questions & Answers

Hi,

Code:

history 800 | grep mail

  387  mailx -s "test from `hostname`" mohtashims@gmail.com  < /dev/null
  388  mailx -s  -a /tmp/hello.zip "test from `hostname`" mohtashims@gmail.com  < /dev/null
  389  mailx -s  "test from `hostname`" mohtashims@gmail.com  < /dev/null
  390  mailx -s  "test from `hostname`" mohtashims@gmail.com  < "Hello"
  392  mailx

Now I need the command in history at position 391, how could I ?

Kindly help.

Code:

history 800 | grep 391

?

Code:

history 400 | grep -e '^391'
#OR
fc 391 391 # and clear the buffer before exiting

The problem with this is

history 800 | grep 391
It grep for any command that has the string '391' which is not desired.

The problem with the below is

history 400 | grep -e '^391'

I do not have the -e option with my grep.

grep: illegal option -- e
Usage: grep -hblcnsviw pattern file . . .

SunOS mymachine 5.10 Generic_144488-07 sun4v sparc SUNW,SPARC-Enterprise-T5220

fc 391 391 # and clear the buffer before exiting
This works however not sure about "# and clear the buffer before exiting". Can you please explain?

Please try to use this :

history | awk '$1~/72/{print $0}'

You don't need "-e" option for grep. And I think '# and clear the buffer before exiting" it's about clearing of the buffer of an editor. But you can do

Code:

history 391 391