UNIX for Dummies Questions & Answers

Hi

I am trying to list all files in every subdirectory from a given location. However, I realise that 1 folder will have files that I am not interested in. This is using a .csh file to execute

I have tried different scripts but to no avail. My current incarnation is below. Would someone be able to help please? So basically, list all files in every subdirectory, except files in the subdirectory "ignoreme". The $DOWNLOADSFOLDER exists and without the prune I am getting all the files.

Thanks in advance

Code:

 
echo `find $DOWNLOADSFOLDER -type f -path '$DOWNLOADSFOLDER/ignoreme' -prune`

Try leaving $DOWNLOADSFOLDER/ out of the prune.

See if this works for you:

Code:

find $DOWNLOADSFOLDER -type f \! -path "$DOWNLOADSFOLDER/ignoreme"

Here is one also

Code:

find $DOWNLOADSFOLDER ! \( -type d -name 'ignoreme' -prune \) -type f

Thank you Peasant. The following would also solve the issue

Code:

find $DOWNLOADSFOLDER \( ! -name 'ignoreme' -o -prune \) -type f

But, I really don't understand how it works. So, please tell me what is the difference between the above one (your solution) and the one which I have given and suggest me which one is efficient.