UNIX for Dummies Questions & Answers

Alright so I've tried a couple different things that at first glance, looked like they worked.

Code:

find . -maxdepth 5 -type d -daystart -mtime 1 | xargs du -h

Which seems to ignore the previous commands such as depth and modified time.

Code:

find ..  -maxdepth 2 -type d -daystart -ctime 1 | xargs ls -dsh

Which appears to adhere to maxdepth and modified time, however gives an incorrect directory size..
Output:

Code:

8.0K ..
8.0K ../scripting/Final_Testing
8.0K ../scripting/Prelim_Testing

What I actually want, is to check to see if files in a directory have been modified, and then list the directory name and file size associated with it.

I'm very tired today, and I feel a fresh pair of eyes may help, thanks in advance
Michael

I'll give it a shot

Code:

find "$PWD" -type f -daystart  -mtime -1 -exec du -sk {} \; | \
sed -e "s#\(/.*/\)#&\t#g" -e "s# #_#g" | \
awk '{a[$(NF-1)]=a[$(NF -1)] +$1 } {b[$(NF-1)]=b[$(NF -1)] $NF" "} END {for (i in a) print "DIR "i,"INCREASED SIZE FOR " a[i]/1024"MB","DELTA FILES : "b[i] } '

$PWD is starting dir, we need absolute paths.
Used du -sk for numeric in KB.
-type f instead of -type d you used.
If files in directory have spaces they are represented as _ instead of <space>.
I'm sure it has bugs

Regards
Peasant.

Please re-phrase the question avoiding the ambiguous "it" and give a detailed example of source data and expected output where the figures are correct. Please make the required units (blocks, kilobytes, whatever) clear.

Hmm. What is "file size associated with it"?

Oh sorry, so I don't want individual files to be recorded, I only want the size of the folder.

But using ls, most folders return a size of like 8kb, whereas I know matter of factly I have hundreds of MB in some folders.


The output ideally would look something like

Code:

134M .
12M ./folder1
4M ./folder1/1
8M ./folder1/2
8KB ./folder2
1MB ./folder3

Something like that, with total filesize WITHIN the folder, not the files themselves

The idea behind this is that I can then export these to a csv file, open it in excel and create a % of growth formula to be used daily and track where the biggest changes in data occur

The output from say "ls -lad" on a directory is the size of the directory file itself (how much space it takes to hold a list of files, properties, permissions and location on disc).

I don't have your version of "find" and cannot verify "-daystart" but I can see that the "-mtime" operator needs to be relative (-mtime -1) rather than absolute (-mtime 1). There is much variation in the syntax and behaviour of the "find" command. Try it on your system.

For example:

Code:

find . -maxdepth 5 -type d -mtime -1 | xargs du -sh

daystart




I have a few different outputs for mtime, I don't overly understand the difference between 1 and -1 though

I honestly thought the idea of daystart was to start mtime from like, 12am, but that command was sorta thrown at me, so I just used it.

Also from the above image, I honestly can't tell what mtime 1 is showing me, although mtime-1 and 0 both seem to show what I did yesterday

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I need more sleep, my brain is fried, working on little sleep != good
I'll try have another look later, thanks for all your help

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Interesting looking code, I ran it and had no bugs, I really don't understand awk or sed but that's purely because I haven't had enough experience with them, are you able to explain your code at all?