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AWK w/ if statements failing.

 
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# 1  
Old 06-08-2011
AWK w/ if statements failing.
I'm converting some code from ksh on my macbook (Version M 1993-12-28 s+) to an older solaris machine with ksh 88.

I can't seem to figure out this line, it worked on the new shell version.

Code:
set -A combo -- $(for x in ${ImageIDs[*]};
do 
nawk -v s=$x 'if($2 == s) getline ; getline if ($1 == "IMAGE_SIZE") print s":"$2"-"$3 ' temp.ASCII ; 
done)

I see this output for every item in the for index:

Code:
Code:
nawk: bailing out at source line 1
nawk: syntax error at source line 1
 context is
>>> if <<< ($2 == s) getline ; getline if ($1 == "IMAGE_SIZE") print s"
:"$2"-"$3
nawk: bailing out at source line 1
nawk: syntax error at source line 1
 context is
>>> if <<< ($2 == s) getline ; getline if ($1 == "IMAGE_SIZE") print s"
:"$2"-"$3
nawk: bailing out at source line 1
nawk: syntax error at source line 1
 context is
>>> if <<< ($2 == s) getline ; getline if ($1 == "IMAGE_SIZE") print s"
:"$2"-"$3

# 2  
Old 06-08-2011
I belive you are missing curly bracers and some ";"
Code:
nawk -v s=$x '{ if($2 == s); getline ; getline; if ($1 == "IMAGE_SIZE") print s":"$2"-"$3 }'

This User Gave Thanks to Peasant For This Post:
nerdcurious
# 3  
Old 06-08-2011
You got it, that was my problem, thank you. I understand the missing braces, but could you explain why I needed an extra ";" ?



Code:
if($2 == s); getline

 
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