UNIX for Dummies Questions & Answers

Basically, you want to enter a value (x), then kill the processes that have pid > than (x)?
Or did I miss something?

i am going to explain it from the beginning

Note: my command is : ps -efo somthing | grep somthing | grep somthing
it is a very very long command which i can't remember right now XD

so the guys helped me with the x thing and it was working fine to me
that was the porpuse of the x

now i have ran the shutdown_script by using for loop on each proccess came out from the final command which is

process_2
process_3
process_4
process_5

(the ones >=600 kb)

Note: final command is : ps -efo somthing | grep somthing | grep somthing | awk -vx=$x '$1>=x{print $NF}'

by running the following

Code:

echo "Enter value: " 
read x 
 
for i in `my_command| awk -vx=$x '$1>=x{print $NF}'`;do
 
shutdown_script $i
 
done

so the processes was shutted down successfully but i had another problem

i want to do another loop that running another script which is

(start_script) on each process i did shutdown but the problem is the process does not exist by running "ps -efo" since it was killed

so i came up with temp file or variable or whatever so the temp will save the processes that i did shutdown by save them in a temp file/variable before shutting them down, and then reuse them again in the starting loop using (start_script)

Try this then, just to be sure:

Code:

TEMPFILE='/tmp/tempfile'
[...]
my_command | awk -vx=$x '$1>=x{print $NF}' > "$TEMPFILE"

thanks alot tuku i'v already done this before but there is a problem of the output of the command. The processes does not show up line by line it is appeared as a single line, for example if i do the following

Code:

my_command | awk -vx=$x '$1>=x{print $NF}' > "$TEMPFILE"
 
echo "$TEMPFILE"

it will show the processes as
process_2 process_3 proccess_4 process_5

instead of showing them line by line
process_2
process_3
process_4
process_5

the output of my_command is

500 kb process_1
600 kb process_2
700 kb process_3
800 kb process_4
700 kb process_5
100 kb process_6

and the output of the final_command is

process_2
process_3
process_4
process_5

and the echo has nothing to do with what i am looking for, it just helps me to know what is the outout of the temp file/variable

I know , just the correct way to view a file is to cat

If you echo "$TEMPFILE", it's a variable and that's the thing I don't understand. This command SHOULD return '/tmp/tempfile'or whatever you entered.

cat file should return the output of the command (the list of processes)