Removing a character


 
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# 1  
Old 05-10-2011
Removing a character

I need to remove square brackets from output of script.

Output is:

Code:
 [121]

and I need to remove the square brackets so I am lett with

Code:
 121

Is sed the only means to do this and if so what are the options?



...ok so far I have managed to get rid of ] by using
Code:
 /usr/bin/sed 's/]//'

but that damn little [ is persistant....

but eventually I managed it by

Code:
 awk -F\[ ' { print $1" "$NF } ' <filename> | sed 's/\]//'

for future reference.

Last edited by rob171171; 05-10-2011 at 05:05 AM..
# 2  
Old 05-10-2011
try these
Code:
sed 's/\[\|]//g'
sed -e 's/]//' -e 's/\[//'
sed 's/]//;s/\[//'

# 3  
Old 05-10-2011
The right way to write it is :

Code:
sed 's/[][]//g' infile

1. The red ones enclosed all the elements that are concerned (that are to be replaced)
2. the closing bracket ] is a special case and should be declared at FIRST in the element list (Just for your info , another special case in the hyphen , the hyphen when within square bracket definition, should be first OR last to be taken as litteral, otherwise it is taken for range definition)

Code:
$ echo '[]]]]]][[[[[[]]]]]]]][[[[1[[[]]2]]][[[]]1]]]][[[' | sed 's/[][]//g'
121


Last edited by ctsgnb; 05-10-2011 at 06:57 AM..
This User Gave Thanks to ctsgnb For This Post:
# 4  
Old 05-10-2011
Many Thanks, will try later to see the difference between my awk & sed command versus ye guys sed
# 5  
Old 05-10-2011
Or simply
Code:
tr -d '[]'

may also help
# 6  
Old 05-10-2011
Thanks all. I'm going to use ctsgnb's suggestion of

Code:
 sed 's/[][]//g' test

as its definitely the most straightforward!
 
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