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Group files by owner and show directory

 
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# 1  
Old 05-01-2011
Group files by owner and show directory
Hello, i would like to find huge files and group them by owners.
To find big files i use this command:
Code:
ls -lR | sort -bnr +4 | head -n 75

which give me 75 biggest files, then i need to see in which subdirectory is every file.
second thing i dont know is how to group those files by owner, could someone help me?, have no idea how to do it.

Was trying to play with 'find' command etc but it dont work like i want
The structure i would like to get is following
Code:
name_user1
drwxr-xr-x   4 user1     root           7 Feb 22  2007 file1
drwxr-xr-x   4 user1     root          15 Feb 23  2007 file2
drwxr-xr-x   4 user1     root          20 Apr 13  2007 file3
drwxr-xr-x   5 user1     root          32 Jul 19  2007 file4
drwxr-xr-x   4 user1     root          46 Jul 30  2007 file5
drwxr-xr-x   5 user1     root          56 Sep 20  2007 file6
dr-xr-xr-x   5 user1     sys           67 Mar 24  2008 file7
name_user2                                             
drwxr-xr-x   8 user2     other          9 Jun 16  2008 file1
drwxr-xr-x   6 user2     root          19 Oct 10 12:50 file2
drwxr-xr-x   5 user2     root          26 Oct 14 18:17 file3
drwxr-xr-x   2 user2     root          35 Nov 13 13:37 file4
drwxr-xr-x  76 user2     root          46 Nov 21 09:01 file5
drwxr-xr-x   6 user2     root          58 Nov 27 07:34 file6
drwxr-xr-x  11 user2     root          62 Jan 12 15:39 file7
drwxr-xr-x   5 user2     root          95 Jan 12 15:57 file8
name_user3                                             
drwxr-xr-x   3 user3     root           3 Jan 13 09:01 file1
drwxr-xr-x   3 user3     other          8 Jan 13 11:17 file2
drwxrwxr-x   5 user3     other         61 Jan 13 13:01 file3

i know that i can get user_name from /etc/passwd but how to make it so nice ordered?
Thanks for you help
# 2  
Old 05-02-2011
Code:
find . -type f -size +100k -ls |sort -k7rn|head -75 |sort -k5

# 3  
Old 05-23-2011
Hello, when i use this command i get following error
Code:
find: Error in processing the argument 100k



that one dosent give any error but its not what i am looking for
Code:
find . -type f -size +100 | sort -k7rn | head -75 | sort -k5

# 4  
Old 05-31-2011
i see that noone knows it
some ideas?
thanks
# 5  
Old 05-31-2011
Quote:
Originally Posted by rdcwayx
Code:
find . -type f -size +100k -ls |sort -k7rn|head -75 |sort -k5

That appears to work ok for me, what problems are you having with it?

Edit: Looking at your problem with the 100k parameter it looks like you are not using the GNU version of find, what platform are you working on?

H.
Last edited by Haqa; 05-31-2011 at 09:21 AM..
# 6  
Old 05-31-2011
HP-UX - its what you mean?
# 7  
Old 05-31-2011
Quote:
Originally Posted by dealer1985
HP-UX - its what you mean?
Ahh, yes, the standard find command on HP-UX only accepts blocks (512 Bytes) or bytes as parameters for the size option. The default is blocks so, your 100k would be "-size +200" or "-size +102400c". Also, the "-ls" option doesn't appear to be supported so use "-exec ls {} \;" instead.

Other than that the sort command and head command should accept those parameters so the command should work.

So the command becomes
Code:
find . -type f -size +102400c -exec ls {} \; |sort -k7rn|head -75 |sort -k5

H.
This User Gave Thanks to Haqa For This Post:
rdcwayx
 
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