UNIX for Dummies Questions & Answers

Is there a command in unix to remove a carriage return character(^M) at the end of a variable value?

Code:

$ FOO="bar
> "
$ echo "$FOO"
bar

$ BAR=$FOO
$ echo "$BAR"
bar

$ BAR=`echo $FOO`
$ echo "$BAR"
bar
$

In other words, "echo" will chomp it when used without quotes.

Before and after I tried to remove the ^M with the echo command, (per your instructions) it did not put an extra line between the output of these commands:
echo $variable
echo $variable
echo $variable
or
echo $bar
echo $bar
echo $bar

Sorry, I must have wrong, ^M must not be a carriage return, at least not to the echo command. After doing the
bar=`echo $variable`, the ^M is still there at the end of the variable bar.

echo "helloworld^M" | sed 's/\^M//'

If u just simply want to chop off the last character ....
do the following ....

echo "hello" | sed 's/.$//'


or u can file streams as input to sed .... ;

The sed command to remove any last character, worked like a champ! Thank you.