UNIX for Dummies Questions & Answers

Hello all, i'm stumped.... I need to list all directories with all there info and exclude the files, then vice versa. I am not sure if I need to string several ls commands together or how to even do that. I believe I need to do some variation of ls -l but need to figure out how to take out the files from this list and leave the directories and vice versa? I am slowly going mad. Can I pipe options together?

I am trying to write a shell script to do this. Once I know the command I need to use would I echo this into my file then run it? This stuff is not coming easy for me at all......

I appreciate any and all help. Struggling in Seattle, citizencro

Code:

ls -ld */

Now how do I get it to do the reverse, showing all files with full info and no directories? Thanks for responding, citizencro

One way ..

Code:

ls -l | grep -v ^d

Code:

find -type f -exec ls -l {} \;

For "full" information:

Code:

cd /start_dir
find . -type f -exec ls -lisad {} \;
find . -type d -exec ls -lisad {} \;