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List directories, subs and files

 
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# 29  
Old 04-04-2011
In case you refer to a 'find . -ls' works
'find . -ls' works fine, but that does not return what I need. It does not allow me to find the name of the file and the folder it belongs to.

When I have a return like this:
Quote:
3366394;0; ./folder/file;file
In excel
  • I can take the last string (cf. file) and
  • subtract if of (./folder/file),
  • resulting in the string ./folder/, which is thus the folder holding the file.
Same for folders:
Quote:
3366394;0; ./folder_level1/folder_level2;folder_level2
  • I can take the last string (cf. folder_level2) and
  • subtract if of (./folder_level1/folder_level2),
  • resulting in the string ./folder_level1/, which is thus the folder holding the folder
With a regular find . -ls, I can not deduce that. Hence, need to get some more info and use more complex stuff.

In case you refer to
Quote:
find . -ls | awk '{match($11,"[^/]*$");type=($3~/^d/)?"directory"Smilie($3~/^-/)?"file"Smilie$3~/^l/)?"link":"other");print $1,type,$11,substr($11,RSTART,RLENGTH)}'
Files and folders with a blank space in their name (e.g. 'this is a file with a few blank spaces'), the returned file name and path is:
./this;this
and not
./this is a file with a few blank spaces;this is a file with a few blank spaces
Last edited by dakke; 04-04-2011 at 11:03 AM..
# 30  
Old 04-04-2011
Hmmm... I'm not following... I thought what you had satisfied your requirements...
Sounds like the requirements have changed.
Please post the output of a sample 'find . -ls' and desired output.
# 31  
Old 04-04-2011
Give a try with this
Code:
find . -ls | awk '{type=($3~/^d/)?"directory":($3~/^-/)?"file":($3~/^l/)?"link":"other";x=y=$0;sub(".*"$10,"",x);sub(".*"$10"[^/]*/","",y);sub(".*",$1 FS type FS x FS y ,$0)}1'

# 32  
Old 04-04-2011
@vgersh99

You did, untill I noticed that the output was not as desired for some files (posted in previous reply). Your output with your code
Quote:
find . -ls |nawk '{match($0,":[0-9][0-9]*");f=substr($0,RSTART+3);match(f,"/[^/]*$");print$1,$3,f,substr(f,RSTART+1)}'
was:
Quote:
1223405;120; ./Folder/Folder/Folder/file.pdf;file.pdf
2539552;40; ./File;File.odt
1519496;0; ./Folder2;Folder2
1519497;0;19497 0 drwxr-xr-x 9 user staff 306 24 okt 2009 ./Virtual Machines.localized/.localized;.localized
1519504;8;19504 8 -r--r--r-- 1 user staff 92 24 okt 2009 ./Folder3/.Folder/de.strings;de.strings
1519503;8;19503 8 -r--r--r-- 1 user staff 86 24 okt 2009 ./Folder3/.Folder/en.strings;en.strings
the issue here is that (last line):
'19503' should not be there, neither should the ' -r--r--r--'. Therefore I applied the other code.

@ ctsgnb
This for now seems to work, will try and report back if not.
Code:
find . -ls | awk '{type=($3~/^d/)?"directory":($3~/^-/)?"file":($3~/^l/)?"link":"other";x=y=$0;sub(".*"$10,"",x);sub(".*"$10"[^/]*/","",y);sub(".*",$1 FS type FS x FS y ,$0)}1'

# 33  
Old 04-04-2011
@dakke,

You could give a feedback also if it works as expected ... Smilie
# 34  
Old 04-04-2011
I know what the problems is, but I need the output of find . -ls processing which produces wrong results....
# 35  
Old 04-04-2011
@vgersh99

Do you want a full find . -ls you mean?

@ctsgnb
Will do. Smilie
 
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