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Top Forums UNIX for Dummies Questions & Answers Help with Data Sorting
# 1  
Old 03-15-2011
Lightbulb Help with Data Sorting

Hi All,
I have a long list made of 4 columns containing entries such as the following example:
Code:
a    b    c    d
0    0    0    0
1    2    1    2
2    5    3    4
3    8    4    6
4    10   9    8
5    15   8    10

So the top row is the header and I need to arrange the data in a way as to verify (using 1 for present or 0 for absent) the occurrence of each entry in the entire grid. My expected output is to keep the header row, place each individual entry in a new single column and then for each of them to put 1 or 0 under a, b, c, or d columns depending on their presence or absence. The output for the above data should look like:
Code:
     a    b    c    d
0    1    1    1    1
1    1    0    1    0
2    1    1    0    1
3    1    0    1    0
4    1    0    1    1
5    1    1    0    0
6    0    0    0    1
8    0    1    1    1    
9    0    0    1    0    
10   0    1    0    1
15   0    1    0    0

Thanks in advance. I'll appreciate your response.

Cheers Smilie
# 2  
Old 03-15-2011
What is present? The row number? How do you determine what to check for?

In other words, why does
2 5 3 4 give 1 1 0 1 ? (rownumber == 2)
# 3  
Old 03-15-2011
Present means existing.

To break it down for example
An entry called 0 is present in all columns a, b, c and d and thus its existence is denoted by 1, 1, 1, and 1 under a, b, c and d;
An entry called 1 is only present in columns a and c, but not in columns b and d. Thus its existence is denoted by a 1 in columns a and c and by a 0 in columns b and d;
Another entry called 2 exists/is present in columns a, b and d but not in column c, and thus its existence is denoted by 1 in columns a, b and d and by a 0 in column c;
the same goes true for other numbers in the entire data set of all columns.
Hope its clear.
# 4  
Old 03-15-2011
Here is a script solution for the example, assuming the file with the data is named file.tmp, and the file separator is a tab
Code:
#!/bin/bash
echo -e " \ta\tb\tc\td"
for i in $(tail -n+2 file.tmp | tr '\t' '\n' | sort -un)
do
  tail -n+2 file.tmp | cut -f1 | grep -w $i 1>/dev/null 2>&1
  let a=1-$?
  tail -n+2 file.tmp | cut -f2 | grep -w $i 1>/dev/null 2>&1
  let b=1-$?
  tail -n+2 file.tmp | cut -f3 | grep -w $i 1>/dev/null 2>&1
  let c=1-$?
  tail -n+2 file.tmp | cut -f4 | grep -w $i 1>/dev/null 2>&1
  let d=1-$?
  echo -e "$i\t$a\t$b\t$c\t$d"
done

This User Gave Thanks to Dahu For This Post:
# 5  
Old 03-15-2011
This worked perfectly !

Could you please comment on the following to let me know what it means. That will be a great help in understanding the code for me to experiment.

Code:
for i in $(tail -n+2 file.tmp | tr '\t' '\n' | sort -un)
do
  tail -n+2 file.tmp | cut -f1 | grep -w $i 1>/dev/null 2>&1
  let a=1-$?

To go one step ahead, in the output, how can I add another column lets say "e" after "d" which contains the sum of values in a, b, c and d. In other words, because 0 was present in all 4 initial columns in file.tmp, it got a value of 1(for existence) in all 4 output columns. How can I generate a column "e" which contains the sum of all these new entries, so inthe case of 0 I should get 4, and so on for the rest of the list.
I know I can do this in excel but I want to learn the command line for this.
Thanks a lot for the useful input.
Smilie
# 6  
Old 03-15-2011
Code:
# cat tst
a    b    c    d
0    0    0    0
1    2    1    2
2    5    3    4
3    8    4    6
4    10   9    8
5    15   8    10
# printf "%s\t%s\t%s\t%s\t%s\n" "" a b c d && awk 'NR>1{for (i=1;i<NF+1;i++) I[$i]=$i;A[$1]=($1==0)?1:$1;B[$2]=($2==0)?1:$2;C[$3]=($3==0)?1:$3;D[$4]=($4==0)?1:$4}END{for (j in I) print I[j],A[j]?1:0,B[j]?1:0,C[j]?1:0,D[j]?1:0}' OFS="\t" tst | sort -k1n
        a       b       c       d
0       1       1       1       1
1       1       0       1       0
2       1       1       0       1
3       1       0       1       0
4       1       0       1       1
5       1       1       0       0
6       0       0       0       1
8       0       1       1       1
9       0       0       1       0
10      0       1       0       1
15      0       1       0       0
#

This User Gave Thanks to ctsgnb For This Post:
# 7  
Old 03-15-2011
could you please comment on the code to make me understand a bit

thanks for your help though Smilie
 

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