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# 1  
Old 03-11-2011
Renaming files in one file from names in other

Hi Guys,
I have a small problem of renaming multiple files. For example I have names of a set of files in one directory like

and the other set corresponding to the same is

Now what I would like is that the new renamed file looks like this so that it computes the mean of the last two values in first set ; for example
K2_34625-34675 should become K2_34650 and so on for the other names in the first set,
then these new names have to be used to rename the second set of files for example ;
U_P_321_9_3_11.ab1 should become K2_36450.ab1, and so on.

Could anyone please help out on this as I have a long list like this.

Hope to get some answers

Thanx in advance

Moderator's Comments:
Mod Comment
Please use code tags when posting data and code samples!

---------- Post updated 03-11-11 at 04:30 AM ---------- Previous update was 03-10-11 at 04:02 PM ----------

Thank you moderator for correcting my input .... I was not aware of such a thing as code tag.

Hope now the input is OK for a reply from the forum.

Looking forward to it .... Thanks in advance Smilie

Last edited by vgersh99; 03-10-2011 at 05:05 PM.. Reason: code tags, please!
# 2  
Old 03-12-2011
Help with controlling string elements

Hi All

Has anyone had a few moments to look at my previous query,

I'll really appreciate feedback of any sort to help me start experimenting myself,

I have a general difficulty in understanding how to control single elements within a string. An example,

XYZ1234      ABCD5678

My expected output is :

ABCD1234     XYZ5678  (swapping subset of string elements of choice)
XYZ37            ACBD1214 (making calculations using string elements)


Could someone illuminate on such problems please

Thanks in advance Smilie

PS: I'm a beginner to UNIX
# 3  
Old 03-12-2011
[ctsgnb@shell ~/sand]$ cat f1
[ctsgnb@shell ~/sand]$ cat f2
[ctsgnb@shell ~/sand]$ paste f2 f1 | while read a b
> do
> t=${b##*_???}
> v=$(echo $b | sed 's/.*_...//;s/-.../-/')
> n=${b%$t}$(( -($v) )).${a#*.}
> echo "mv $a $n"
> done
mv U_P_321_9_3_11.ab1 K2_34650.ab1
mv U_P_322_9_3_11.ab1 K7_98820.ab1
mv U_P_323_9_3_11.ab1 K12_7733220.ab1
[ctsgnb@shell ~/sand]$

If it does what you want then just change the echo "mv $a $n" with mv "$a $n"

---------- Post updated at 12:42 AM ---------- Previous update was at 12:34 AM ----------

please give more clue about the caculation for the renaming :

34625-34675 = -50
and what should be calculated in the

I assumed you want to keep the first 3 number unchanged so that is becomes:
so the new name will be K12_7733220.ab1
by the way, i also assume you have the same number of entries in your both set of files
This User Gave Thanks to ctsgnb For This Post:
# 4  
Old 03-13-2011
Thanks CTSGNB,
Your suggestion is producing the exact output as you mentioned, but my expected outcome for input is as follows

output before calculation
For the calculation I want to calculate the mean of the two numbers separated by "-" which does not imply subtraction. Thus my final expected output for each entry in both set of files should be for example:
Please not the one set of entries are just assigned names eg. K2_34625-34675 upon which the calculation need to be done and then assigned the modified name to another entry (those ending with .ab1) which are real data containing files to be renamed.

I hope I'm clear enough.

Thank you for looking into this.

Have a nice sunday.
# 5  
Old 03-13-2011
ok you mean the "average" of these numbers ?
so give a try to
paste f2 f1 | while read a b
v=$(echo $b | sed 's/.*_//;s/-/+/')
n=${b%$t}$(( ($v) / 2 )).${a#*.}
echo "mv $a $n"

This should give you something like :

mv U_P_321_9_3_11.ab1 K2_34650.ab1
mv U_P_322_9_3_11.ab1 K7_988973.ab1
mv U_P_323_9_3_11.ab1 K12_4253992.ab1

if it fits your needs, just change
echo "mv $a $n"

mv "$a $n"

# 6  
Old 03-13-2011
Hi there,

I tried your code but its giving me the following output:

:~ noel$ paste b.txt a.txt | while read a b
> do
> t=${b##*_}
> v=$(echo $b | sed 's/.*_//;s/-/+/')
> n=${b%$t}$(( ($v) / 2 )).${a#*.}
> mv "$a $n"
> done 
usage: mv [-f | -i | -n] [-v] source target
       mv [-f | -i | -n] [-v] source ... directory
usage: mv [-f | -i | -n] [-v] source target
       mv [-f | -i | -n] [-v] source ... directory
usage: mv [-f | -i | -n] [-v] source target
       mv [-f | -i | -n] [-v] source ... directory
-bash: () / 2 : syntax error: operand expected (error token is ") / 2 ")

but when I remove the "" in the mv command I get

> mv $a $n> done
mv: rename U_P_321_9_3_11.ab1 to K2_34650.ab1: No such file or directory
mv: rename U_P_322_9_3_11.ab1 to K7_988973.ab1: No such file or directory
mv: rename U_P_323_9_3_11.ab1 to K12_4253992.ab1: No such file or directory
-bash: () / 2 : syntax error: operand expected (error token is ") / 2 ")

Is this because a.txt and b.txt in this case are files containing entries and not real .ab1 files ??

I will do this will real files soons and let you know but if you can comment on the code to simplfy what its doing its will be a big help. At the moment I dont understand it

Thanks and have a nice evening. Smilie
# 7  
Old 03-13-2011
Try to run it using korn shell (ksh).

1) Are all your U_P*.ab1 files located in the same directory ? if so, in which one ?
2) Are all your K*-* files located in the same directory ? if so, in which one ?
3) This link should help understanding the code of pattern matching operator : String Operators (Learning the Korn Shell, 2nd Edition) especially Table 4-9.
For the $(( ... )) notation, you can read Numeric Variables and Arithmetic (Learning the Korn Shell, 2nd Edition)

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