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variable passed to awk

 
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# 1  
Old 09-15-2004
Question variable passed to awk
Anybody know what's wrong with this syntax?

awk -v job="$job" 'BEGIN { FS="|"}
{print $1,$2," ",$4," ",$3\n,$5,"\n"}' list


It's keeping give me this message:

awk: syntax error near line 1
awk: bailing out near line 1


It seems awk has problem with my BEGIN command.

Any help is appreciated!
# 2  
Old 09-15-2004
With just a quick look, you don't have an END statement - unless you didn't post the whole thing. Also make sure you are using the correct awk - at least on Solaris (2.6) /usr/bin/awk and /usr/xpg4/bin/awk are different - no -v option on /usr/bin/awk.
Last edited by RTM; 09-15-2004 at 01:05 PM..
# 3  
Old 09-15-2004
Question END statement
I don't think I have to put END statement ???
# 4  
Old 09-15-2004
Like I stated - just a quick look. And it seems to work on one version of awk (even without the END statement) but not the one normally in the PATH (see my other post - it was updated). What's your OS and version?
# 5  
Old 09-15-2004
Version?
How do I know?
# 6  
Old 09-15-2004
The command uname -a should give you the output to find the version and OS.
# 7  
Old 09-15-2004
Question Version?
Here it is:
I guess it's SonOS and version 5.7?


SunOS milford2 5.7 Generic_106541-19 sun4u sparc SUNW,Ultra-1
 
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