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variable passed to awk

 
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# 1  
Old 09-14-2004
Question variable passed to awk
Does anybody know how to print a variable passed to awk command?

awk -F"|" 'BEGIN {print $job,"\n","Question \n"} {print $1,$2$4," ",$3}' "job=$job1" file1


I am trying to pass job the variable job1.

the output is blank.

??
# 2  
Old 09-14-2004
Use the -v switch to pass in a variable to Awk. Go to ]GNU and search for gAwk documentation for more details.

Code:
awk -v job=$job BEGIN '{FS= "|"; print "$job\n","Question \n"} {print $1,$2,$4," ",$3}'  file1

Last edited by google; 09-14-2004 at 10:07 PM..
# 3  
Old 09-15-2004
It's still not working.
variable $job is not empty string. but when it printed, it always prints JOB $job


echo job is $job
nawk -F"|" -v JOB=$job 'BEGIN {print "JOB ","$job\n"}
{print $1,$2," ",$4,"\n"}' list
# 4  
Old 09-15-2004
Thats because you are using "print" and placing job in quotes. Try using printf instead and using the %s notation.
 
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