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help with shell scripting argument


 
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# 1  
Old 11-16-2010
help with shell scripting argument

Code:
#!/bin/bash

echo "enter a file or directory name"
read name
if [ -f $name ]
        then
        echo " argument is file "
        ls -l $name | awk '{print $1,}'
        elif [ ???  $name ]
        echo " argument is a directory"
        ls -l $name | awk '{print $1}'
fi

what i am trying to do. get input file or directory name from user.
if it is a regular file, print permission or if it is a directory, print permissions.
i know " -f " means regular file but how to ask for directory. in other words i don't know
Code:
elif [ ???? $name]

any help will be appreciated.

Last edited by Scott; 11-16-2010 at 05:58 PM.. Reason: Please use code tags
# 2  
Old 11-16-2010
-d

---
This User Gave Thanks to Scrutinizer For This Post:
# 3  
Old 11-16-2010
Debian thanks

thank you.
Smilie
# 4  
Old 11-16-2010
see man test or man ksh for [...]. There is -d for direcotry, -l for link, -L for something else to do with links? A valid path can also be a named pipe, a raw or cooked device, etc. You can also do
Code:
 
ls -ld $name | read ls
case "$ls" in
(d*)
   echo " argument is a directory" >&2
   ls -l $name
   ;;
(-*)
   echo " argument is file " >&2
   echo "$ls"
   ;;
(*)
   echo "Not a file or directory: $ls" >&2
   ;;
esac | awk '{print $1}'

This User Gave Thanks to DGPickett For This Post:
 

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